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       #Post#: 8--------------------------------------------------
       Q1 (b)
   DIR By: e_atas
       Date: October 27, 2012, 6:03 pm
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       Could you please provide more details for Q1 section b? I
       couldn't understand precisely from the model answers. Thanks.
       #Post#: 9--------------------------------------------------
       Re: Q1 (b)
   DIR By: Francesco_Longo
       Date: October 28, 2012, 7:05 am
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       --- Quote from: e_atas link ---
       >
       > Could you please provide more details for Q1 section b? I
       couldn't understand precisely from the model answers. Thanks.
       >
       --- End Quote ---
       If I understood well, the basic idea is very simple. With "R"
       you can reproduce all the other operator, that is "P" and "I";
       for this reason you can say that it is complete. But, for
       example, using only "P" you're not able to obtain an indifferent
       relationship "I", because if xPy it could never be xIy.
       Similarly for "I". If xIy you will never reach that xPy. Hence,
       R is complete because you can recover all the other preferences'
       relationship with it, and the same is not true for P and I.
       Considering lexicographic preferences, you don't have the
       relation "I", but just "P" (and "R"), so "P" is enough to cover
       all the preferences's relationship of that specific preferences
       (lexicographic).
       Anyway, it is better to wait Julia's answer.
       #Post#: 10--------------------------------------------------
       Re: Q1 (b)
   DIR By: Julia.Wirtz
       Date: October 30, 2012, 7:01 am
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       Yes, I think your answer is very good. I don't have anything to
       add, really.
       #Post#: 11--------------------------------------------------
       Re: Q1 (b)
   DIR By: e_atas
       Date: October 30, 2012, 3:24 pm
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       Thanks a lot! It was quite helpful.
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