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#Post#: 69--------------------------------------------------
p1
DIR By: zacker93
Date: January 9, 2014, 5:47 am
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Como coņo se plotea la segunda funcion????
>> x=0:0.01:4;
>> y=sinh(exp(-x));
>> plot(x,y)
>> grid
>> hold on
>> y2=0.5*(1-sqrt(4*x-1*x.^2));
>> y3=0.5*(1+sqrt(4*x-1*x.^2));
>> plot(x,y2)
>> plot(x,y3)
apartado b)
>> p1=fzero('0.5*(1+sqrt(4*x-1*x.^2))-sinh(exp(-x))',[0 1])
>> p2=fzero('0.5*(1-sqrt(4*x-1*x.^2))-sinh(exp(-x))',[3 4])
>> A1=quad('sinh(exp(-x))-0.5*(1+sqrt(4*x-1*x.^2))',0,p1)
>> A2=quad('sinh(exp(-x))-0.5*(1-sqrt(4*x-1*x.^2))',1,p2)
#Post#: 70--------------------------------------------------
Re: p1
DIR By: antay
Date: January 9, 2014, 5:55 am
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Pero solo te sale la del senh(exp(x))... y el dibujo de las
dos??Vamos a por el B!!!
#Post#: 71--------------------------------------------------
Re: p1
DIR By: zacker93
Date: January 9, 2014, 5:55 am
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tio es lo que estoy preguntando
#Post#: 72--------------------------------------------------
Re: p1
DIR By: antay
Date: January 9, 2014, 6:17 am
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El corte de la derecha he puesto:
>> p=fzero('sinh(exp(-x))-(1/2*sqrt(4*x-x.^2)+1)',[0,2])
y me da p=0.0208
el area me da
>> A=quad('-sinh(exp(-x))+1/2*(1-sqrt(4*x-x.^2))',p2,p1)
A =
2.2029
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