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#Post#: 326--------------------------------------------------
Database: Explosion yield calculations
By: Dutch Date: February 21, 2021, 4:49 pm
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There are several ways to calculate explosion energy. A great
example of this is the Turbolaser yield calculations thread
HTML https://rodentwarsnet.createaforum.com/database/turbolaser-yield-calculations-thread/,<br
/>where both methods are used.
Radius:
Figure out the radius (distance from edge to center) of the
explosion. Then, use one of these calculators to find out the
yield:
Conventional Explosives Effects Calculator
HTML https://www.alternatewars.com/BBOW/Weapons/Conv_Explosive_Calculator.htm<br
/>(Dutch's favorite radius calculator)
Nuclear Weapon Effects Calculator
HTML http://www.stardestroyer.net/Empire/Science/Nuke.html
(for very
large blasts only)
NUKEMAP
HTML https://nuclearsecrecy.com/nukemap/
(for estimating the overall
effect)
This method tends to underestimate yields for smaller explosions
(below about 100g), and so is very subjective due to how much it
is based on the calculator's conjecture. See here
HTML https://vsbattles.fandom.com/wiki/Explosion_Yield_Calculations<br
/>for a less subjective way to estimate by radius.
Destruction:
To find out the energy this way, just figure out how much
destruction the blast caused. If it vaporized 100 grams of iron,
you can calculate it from that, as iron requires 7.63 MJ/kg to
vaporize
HTML http://www.stardestroyer.net/Empire/Science/Asteroids.html.
Just
multiply the amount of iron melted (in kilograms) by 7.63,
getting an answer of, in this case, 0.763MJ. Then you can
convert it into TNT, using this calculator (convert your answer
to joules first):
Joules to kilograms-of-TNT
HTML https://www.justintools.com/unit-conversion/energy.php?k1=joules&k2=kilograms-of-TNT
This method is pretty exact by our standards, but remember
that specific heat changes with temperature (the figures we use
are averages), so it will never be experiment-level.
Or, if the blast violently fragmented 250 cubic centimeters of
granite, then according to a VS Battles Wiki user
HTML https://vsbattles.fandom.com/wiki/User_blog:Spinosaurus75DinosaurFan/Some_missing_destruction_values#Granite<br
/>we should multiply 250 by the violent fragmentation energy of
granite (175 J/cc). This gives us 43750 joules, or 43.750
kilojoules.
The destruction-energy method is only a guesstimate. Though
it admittedly does not reflect the complex nature of material
interactions in real life, comparing it to other methods shows
that it is precise enough for the purpose of rough
approximation.
KE:
Say an explosion hurls 100g of material away. We know that the
yield of said explosion must be at least equal to the kinetic
energy of the material. So if the material is thrown at about
100 m/s, then the KE is roughly 500,000 joules. Now, this is of
course an underestimation since it is the minimum, only
sufficient to hurl away the material with no other effects
(melting, fireballs, other shockwave effects, vaporization,
radiation). For instance, this method is used along with the
melting method here
HTML https://rodentwarsnet.createaforum.com/database/laser-cannon-yield-thread/msg501/#msg501.
Resources:
VS Battles Wiki: Explosion Yield Calculations
HTML https://vsbattles.fandom.com/wiki/Explosion_Yield_Calculations
VS Battles Wiki: Table of Destruction Values
HTML https://vsbattles.fandom.com/wiki/Calculations#Table_of_Destruction_Values
Some missing destruction values
HTML https://vsbattles.fandom.com/wiki/User_blog:Spinosaurus75DinosaurFan/Some_missing_destruction_values
StarDestroyer.net: Asteroid Destruction Calculator
HTML http://www.stardestroyer.net/Empire/Science/Asteroids.html
StarDestroyer.net: Nuclear Weapon Effects Calculator
HTML http://www.stardestroyer.net/Empire/Science/Nuke.html
Conventional Explosives Effects Calculator
HTML https://www.alternatewars.com/BBOW/Weapons/Conv_Explosive_Calculator.htm<br
/>
NUKEMAP
HTML https://nuclearsecrecy.com/nukemap/
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