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#Post#: 960--------------------------------------------------
green tabby + purple tabby = turquoise tabby [private]
DIR By: Puddincat
Date: August 18, 2013, 5:09 pm
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asdffghjjkl
k i already know that parents without white can't make white
children
cats with white can have blue eyes and without can't
points have to have blue eyes
that's all pretty much
#Post#: 969--------------------------------------------------
Re: green tabby + purple tabby = turquoise tabby [private]
DIR By: Pineybear
Date: August 18, 2013, 9:23 pm
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Okay.
^^
Do you know about the black factor? (Basically lesson one.)
#Post#: 972--------------------------------------------------
Re: green tabby + purple tabby = turquoise tabby [private]
DIR By: Puddincat
Date: August 18, 2013, 9:59 pm
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Nu
#Post#: 973--------------------------------------------------
Re: green tabby + purple tabby = turquoise tabby [private]
DIR By: Pineybear
Date: August 18, 2013, 10:08 pm
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Okay. So basically you want me to start from the top?
The black factor contains of six colors. The three main, and the
dilutions.
Black, chocolate, cinnamon.
Would be the order, black being the darkest, and not being able
to be masked.
Black will carry the chocolate, or cinnamon, but never both.
Blue, lilac, fawn.
"Blue" is basically gray/grey. (Imma use grey)
So, when doing pairings, the main will always carry dilute.
Dilutes won't have the ability to create main-pelted cats.
Example:
Black xx lilac
Black, blue, lilac
As lilac is already a dilute, and black is not.
Try these:
Blue xx cinnamon
Chocolate xx black
Lilac xx fawn
#Post#: 974--------------------------------------------------
Re: green tabby + purple tabby = turquoise tabby [private]
DIR By: Puddincat
Date: August 18, 2013, 10:44 pm
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Blue, black, cinnamon
Chocolate, black
Blue, lilac, fawn
#Post#: 975--------------------------------------------------
Re: green tabby + purple tabby = turquoise tabby [private]
DIR By: Pineybear
Date: August 18, 2013, 11:01 pm
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--- Quote from: Puddincat link ---
>
> Blue, black, cinnamon
>
> Chocolate, black
>
> Blue, lilac, fawn
>
--- End Quote ---
Oops, I forgot to tell you, the dark will onlY be affected if
the black or blue cat is a parent.
Blue xx cinnamon
Blue, cinnamon, fawn
Chocolate xx black
Chocolate, lilac, black, blue
Lilac xx fawn
Lilac, fawn
#Post#: 976--------------------------------------------------
Re: green tabby + purple tabby = turquoise tabby [private]
DIR By: Puddincat
Date: August 18, 2013, 11:17 pm
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I don't really get it
But I got a question can the parents' patterns always be options
for kits? Like black x brown tabby could black and brown tabby
always be options?
#Post#: 977--------------------------------------------------
Re: green tabby + purple tabby = turquoise tabby [private]
DIR By: Pineybear
Date: August 18, 2013, 11:31 pm
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Yes.
[font=georgia]Okay, so cinnamon and chocolate are just like
black, except both are recessive, that's why they are lowercase.
Now, the order of dominance is Black > Chocolate > Cinnamon.
Cinnamon requires two copies of the gene to show.
Cinnamon covers up cinnamon, so it can have two or one copy to
show, but remember black will cover it up.
When we do a pair, you line up the parents like this:
Male x Female
Black x Chocolate
You don't have to type 'male x female', that's just for
reference.
You can either right it that way, and put what the cat carries
or you assume it carries in parentheses, OR...
You can write out the genotypes...
----------
COMPARE
Words
Black(carrying chocolate) x Cinnamon
Genotypes
Bb x b1b1
----------
Now, here's a quick ref for when you practice:
[spoiler=Quick Ref for Practice]
Black > Chocolate > Cinnamon
Black -- B (dominant)
Chocolate -- b (recessive)
Cinnamon -- b1 (recessive)
[/spoiler]
[font=georgia]
PRACTICE PAIRS
[use genotypes or words, I don't care]
Black (carrying chocolate) x Cinnamon
Cinnamon x Chocolate
Chocolate x Chocolate
Black x Cinnamon
Chocolate (carrying cinnamon) x Cinnamon
Take your time ^_^
No, cinnamon and chocolate litters cannot have black.
The black factor itself contains all three colors, where
cinnamon and chocolate are lighter mutations of black.
For the parents, you can write the genotypes or the words, but
for the kit options you need to write out the actual possible
colors, and you don't have to say what they are carrying.
The genotype is the genetic makeup of the cat (the cat is BB, or
bb, etc.)
The phenotype is the outside color (the cat is black)
For the kits, you need to write the phenotypes, but for the
parents, either is fine, as it is reference when working it out.
Now, the genotypes you would get with this would actually be:
Bb1
bb1
Because, you take one letter from each parent, and you don't
repeat if they are 'homozygous', which means they have double of
the same allele (each letter of a gene, either recessive or
dominant)
Here's what I mean:
Now, the father is black, carrying chocolate, so they are Bb.
The mother is cinnamon, b1b1.
Now, take one allele from each parent.
Bb1 - I took the B from the dad and b1 from the mom. Notice, the
mom has two b1 genes, but you don't have to put this twice.
bb1 -I took the b from the dad and the b1 from the mom.
So, possible colors from this litter are Black and chocolate,
ignoring what they carry.
Okay, sorry for all the info in this post xD
Do you have questions?
#Post#: 978--------------------------------------------------
Re: green tabby + purple tabby = turquoise tabby [private]
DIR By: Puddincat
Date: August 18, 2013, 11:40 pm
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I'll do it later I'm in my phone and it's hard to do stuff Dx
#Post#: 979--------------------------------------------------
Re: green tabby + purple tabby = turquoise tabby [private]
DIR By: Pineybear
Date: August 18, 2013, 11:59 pm
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;) that's fine. I'm not on a computer either.
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