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       #Post#: 1518--------------------------------------------------
       Problem of the week-10/12/12
   DIR By: Michel
       Date: December 10, 2012, 9:17 am
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       Sorry I'm a bit late with this, but it's simple;)
       a solution of Salt A  was electrolysed, and three gases X, Y and
       Z were obtained as major products. The pH of the solution
       increased as the electrolysis progressed, and Na+ was confirmed
       present in the solution.
       When gases X and Y are reacted at high temperatures, a toxic gas
       B is one product of the reaction.
       Mixing some of Y with B and heating in the presence of finely
       divided Cu/ZnO/Al2O3 catalyst gives methanol.
       Identify all the unknown compounds.
       #Post#: 1525--------------------------------------------------
       Re: Problem of the week-10/12/12
   DIR By: Shiva
       Date: December 10, 2012, 1:42 pm
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       B- Carbon monoxide?
       Y- Hydrogen
       A - Sodium acetate?
       Still working on it.
       Shiva
       #Post#: 1527--------------------------------------------------
       Re: Problem of the week-10/12/12
   DIR By: Henry
       Date: December 10, 2012, 1:59 pm
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       I would agree with Shiva.
       X = Carbon Dioxide
       Y = Hydrogen Gas
       B = Carbon Monoxide
       Z = Ethane
       A = Sodium Acetate
       If B is CO and Y is H2, X has to be CO2 because:
       CO2 + H2 -> CO + H2O
       As said by Michel, X + Y -> B
       B has to be CO because CO reacts with H2 in the presence of
       Copper Zeolite to form Methanol.
       I would also take a guess that A is Sodium Acetate and Z being
       Ethane.
       #Post#: 1529--------------------------------------------------
       Re: Problem of the week-10/12/12
   DIR By: Michel
       Date: December 10, 2012, 4:21 pm
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       Yes. Correct:)
       Thumbs up Shiva, Henry:)  +10 Henry.
       Kolbe electrolysis of an acetate salt in the general form
       2RCOOM==> R-R + CO2 + H2O + MOH
       M is a metal ion.
       Of course this is a highly coincise description, as the reaction
       proceeds via free radical mechanism, and various  intermediates
       and side products are possible. This electrolysis provides a
       good route to symmetrical alkanes in the laboratory.
       Hmmn...I make the question tricky and it sits up for three
       weeks, I try to simplify and it's solved the  same day it's
       posted!
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