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       #Post#: 1132--------------------------------------------------
       Solve: Organic chem question
   DIR By: Michel
       Date: November 16, 2012, 1:06 am
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       A useful organic compound R(C6H10O) reacts with hydroxylamine
       and 2,4-dinitrophenylhydrazine to give crystalline derivatives S
       and T. On treatment with iodine and NaOH solution, R forms
       iodoform but does not form any silver mirror when treated with
       Tollen's reagent. It decolorises a solution of Br2 in CCl4,
       forming compound V(C6H10Br2O). Vigorous oxidation of R using
       chromic acid gives propanoic acid as one of the products.
       Compound R has an isomer W which does not give iodoform but
       under similar oxidation yields acetic acid as one of its
       products. Show how you interpret all the reactions and suggest
       names for R,S,T,V and W
       #Post#: 1137--------------------------------------------------
       Re: Solve: Organic chem question
   DIR By: Michel
       Date: November 17, 2012, 4:01 am
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       Ne replys?
       #Post#: 1160--------------------------------------------------
       Re: Solve: Organic chem question
   DIR By: Chemist@
       Date: November 19, 2012, 7:44 am
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       R=hex-3-en-2-one;
       S=hex-3-en-2-one oxime;
       T=hex-3-en;
       V=3,4-dibromo-2-hexanone;
       W= maybe hex-2-en-3-one.
       Ketone+hydroxylamine=oxime;
       Ketone+2,4-dinitrophenylhydrazine=alkane (in this case alkene);
       Iodoform reaction=methyl group in the ketone;
       Oxidation=cleavage of the double bond, meaning that the ketone
       has a CH3CH2CH=group;
       Everything combined should give the previously mentioned
       compounds.
       #Post#: 1162--------------------------------------------------
       Re: Solve: Organic chem question
   DIR By: Michel
       Date: November 19, 2012, 9:32 am
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       Correct :)
       #Post#: 1163--------------------------------------------------
       Re: Solve: Organic chem question
   DIR By: Michel
       Date: November 19, 2012, 9:44 am
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       With 2,4-dinitrophenylhydrazine, you get
       hex-3-ene-2,4-dinitrophenylhydrazone
       #Post#: 1164--------------------------------------------------
       Re: Solve: Organic chem question
   DIR By: Michel
       Date: November 19, 2012, 9:49 am
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       Treating with a strong base can give the 2-phenyl-3-hexene
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