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       #Post#: 1012--------------------------------------------------
       Problem of the week-29/10/12
   DIR By: Michel
       Date: October 28, 2012, 6:05 pm
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       Here's one for open discussion and analysis ;)
       During the electrolysis of a solution containing 2.5 M NaCl and
       2M Al2(SO4)3 using a copper anode and an Iron cathode, and a 9V
       battery, it is found that one electrode reduces in mass slowly,
       while the mass change in the other electrode isn't much. The
       cell was run for 6 hours and during this period the electrolyte
       assumed two different colors, apart from the initial colorless
       solution. Briefly explain the chemistry of the electrolysis;
       including which electrode significantly reduced in mass, and the
       two different colors you expect the electrolyte to have during
       the course of the electrolysis.
       #Post#: 1025--------------------------------------------------
       Re: Problem of the week-29/10/12
   DIR By: Michel
       Date: October 31, 2012, 12:32 am
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       No takers? I assumed we'd love a break from calculating molar
       masses and finding unknown compounds :|
       #Post#: 1032--------------------------------------------------
       Re: Problem of the week-29/10/12
   DIR By: Chris
       Date: November 1, 2012, 9:02 am
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       no idea...:O
       #Post#: 1039--------------------------------------------------
       Re: Problem of the week-29/10/12
   DIR By: Michel
       Date: November 2, 2012, 9:25 am
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       --- Quote from: Chris link ---
       >
       > no idea...:O
       >
       --- End Quote ---
       really the problem is simple and almost straightforward; Come
       on! You should have some ideas! and you can say your Ideas...
       #Post#: 1049--------------------------------------------------
       Re: Problem of the week-29/10/12
   DIR By: Michel
       Date: November 5, 2012, 4:06 pm
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       Well...so far no takers :( I'm extending it for this week.  At
       least share your thoughts and opinions
       #Post#: 1059--------------------------------------------------
       Re: Problem of the week-29/10/12
   DIR By: LikeCrazy
       Date: November 6, 2012, 9:06 pm
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       Is it possible for the Al2(SO4)3 to react with the NaCl...
       #Post#: 1062--------------------------------------------------
       Re: Problem of the week-29/10/12
   DIR By: Michel
       Date: November 6, 2012, 9:48 pm
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       No. You won't have any reaction between the ionic species in
       solution before the passahe of the direct current through the
       solution. During the electrolysis, redox reactions will occur,
       not necessarily reaction between NaCl and aluminium sulfate
       #Post#: 1090--------------------------------------------------
       Re: Problem of the week-29/10/12
   DIR By: Michel
       Date: November 10, 2012, 8:38 am
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       hmmn...I just realised we're in the end of another week. Surely
       this question is boring? or difficult? or do you think it's
       plainly wrong?
       I do not like posting a new POTW when the old one remains
       unsolved, but I'm tempted to...
       #Post#: 1107--------------------------------------------------
       Re: Problem of the week-29/10/12
   DIR By: Potla
       Date: November 11, 2012, 8:39 pm
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       I might give it a shot...
       The solution contains the following cations and anions:
       Na+, Al3+, H+;
       SO42-, OH-, Cl-.
       We are using Cu anode and Fe cathode. So H+ gets oxidised to H2,
       and bubbles out of the solution. As Fe is more reactive than Cu,
       it comes to the solution, initially as Fe2+ and later as Fe3+.
       So the mass of the Cu electrode does not change much, the Fe
       electrode gets smaller in mass, and the colour of the solution
       changes from green to yellow.
       Hope that's correct. :)
       #Post#: 1110--------------------------------------------------
       Re: Problem of the week-29/10/12
   DIR By: Michel
       Date: November 12, 2012, 2:07 am
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       --- Quote from: Potla link ---
       >
       > I might give it a shot...
       >
       > The solution contains the following cations and anions:
       > Na+, Al3+, H+;
       > SO42-, OH-, Cl-.
       >
       > We are using Cu anode and Fe cathode. So H+ gets oxidised to
       H2, and bubbles out of the solution. As Fe is more reactive than
       Cu, it comes to the solution, initially as Fe2+ and later as
       Fe3+. So the mass of the Cu electrode does not change much, the
       Fe electrode gets smaller in mass, and the colour of the
       solution changes from green to yellow.
       >
       > Hope that's correct. :)
       >
       --- End Quote ---
       Not exactly what I expected...you got the color changes quite
       allright, but you didn't  get which electrode reduces in mass,
       and why.. Remember, it's NaCl/Al2(SO4)3. The solution isn't
       acidic enough to dissolve Fe. Now you know it's the anode that
       reduces in mass. Can you explain why?
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