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       #Post#: 851--------------------------------------------------
       Re: Problem of the week- 1/10/12 
   DIR By: kushashwa
       Date: October 10, 2012, 10:12 am
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       I think this one is a tricky one , I will answer tomorrow with
       my best try.
       Nice! and thanks!
       #Post#: 852--------------------------------------------------
       Re: Problem of the week- 1/10/12 
   DIR By: Potla
       Date: October 10, 2012, 1:47 pm
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       I guess the compound X is HCHO, Y is H2S, and they react to give
       1,3,5-trithiane (Z).
       HCHO+H2S-->(CH2S)3
       Obviously (CH2S)3 and HCHO have similar molecular formula.
       And so, W is
       CH3-CH2-CH2-CH(CH3)-CH=CH2
       But I still think that the answer I gave is a bit off, because
       KMnO4 in acidic conditions should oxidize HCHO to CO2 readily.
       #Post#: 858--------------------------------------------------
       Re: Problem of the week- 1/10/12 
   DIR By: Michel
       Date: October 12, 2012, 4:40 am
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       --- Quote from: Potla link ---
       >
       > I guess the compound X is HCHO, Y is H2S, and they react to
       give 1,3,5-trithiane (Z).
       > HCHO+H2S-->(CH2S)3
       > Obviously (CH2S)3 and HCHO have similar molecular formula.
       > And so, W is
       > CH3-CH2-CH2-CH(CH3)-CH=CH2
       >
       > But I still think that the answer I gave is a bit off, because
       KMnO4 in acidic conditions should oxidize HCHO to CO2 readily.
       >
       --- End Quote ---
       And that's the correct answer!  Methanal is the gas X, Y is H2S,
       Z is (CH2S)3 I was more concerned with the equations than the
       chemistry ;)
       
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