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       #Post#: 136--------------------------------------------------
       Problem of the week-13/5/12
   DIR By: Michel
       Date: May 12, 2012, 3:01 am
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       I'm a bit too early with this, and it's very simple
       A tomato weighing 60.0g is analysed for sulfur content by
       digestion in concentrated HNO3, followed by precipitation with
       Ba to form BaSO4.
       0.466g of BaSO4 is obtained. What is the % of sulfur in the
       tomato
       #Post#: 2196--------------------------------------------------
       Re: Problem of the week-13/5/12
   DIR By: Potla
       Date: February 25, 2013, 6:41 am
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       0.466 g of BaSO4 means 0.2 equivalents, which can only come from
       0.2 equivalents of Sulfur. Now, the reaction that elemental S
       undergoes in presence of HNO3 involves formation of SO4-2, which
       means that the n-factor is 6. So equivalent weight of S= 32/6,
       so the % S content is (32/6)*(0.2)/60*100%=1.77%.
       So the answer is 1.77%.
       :)
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