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       #Post#: 6--------------------------------------------------
       Unit 4 forum
   DIR By: dluvbell
       Date: September 25, 2014, 12:37 pm
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       Unit 4
       #Post#: 17--------------------------------------------------
       Extra
   DIR By: dluvbell
       Date: October 2, 2014, 9:19 am
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       Enjoy
       #Post#: 38--------------------------------------------------
       HW questions
   DIR By: dluvbell
       Date: October 8, 2014, 8:11 am
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       6.1
       P 321 #3,4,7,8,
       6.2
       P330 #2-9,11,14,15
       6.3: No homework. BUT make sure to know how each graph looks
       like and 5 points you need to know.
       6.4
       P343 #1,3,4,5,6,7,8,9,10,11,14
       6.5
       P353 #7. Make sure how to graph each reciprocal function.
       6.6
       P360 #5-10
       #Post#: 96--------------------------------------------------
       Re: Unit 4 forum
   DIR By: dadougiedude
       Date: November 11, 2014, 2:37 pm
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       State an equivalent expression in terms of the related acute
       angle.
       cot (-pi/4)
       #Post#: 97--------------------------------------------------
       Re: Unit 4 forum
   DIR By: dluvbell
       Date: November 13, 2014, 8:11 pm
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       --- Quote from: DaDougieDude link ---
       >
       > State an equivalent expression in terms of the related acute
       angle.
       >
       > cot (-pi/4)
       >
       --- End Quote ---
       -pi/4 means that you are rotating your terminal arm clock-wise
       (opposite direction of usual rotation) by pi/4.
       Then what is the related acute angle inside of the triangle?
       Then figure out how much you have to rotate your terminal arm to
       get to that angle. It should be 7pi/4.
       So one is cot7pi/4. Another one is located where cot is negative
       since cot is negative in the last quadrant.
       So it will be the second quadrant and it gives the angle of
       3pi/4. Then we have cot3pi/4.
       So the answer is cot7pi/4 and cot3pi/4.
       The key is that we only play with the angle without changing
       anything else.
       #Post#: 98--------------------------------------------------
       Re: Unit 4 forum
   DIR By: Thomath
       Date: November 14, 2014, 1:24 pm
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       FIND THE AREA OF A SECTOR OF A CIRCLE THAT HAS A CENTRAL ANGLE
       OF 13∏/18 and a radius of 12cm. round your answer to the
       nearest tenth.
       #Post#: 99--------------------------------------------------
       Re: Unit 4 forum
   DIR By: dluvbell
       Date: November 14, 2014, 3:45 pm
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       --- Quote from: Thomas link ---
       >
       > FIND THE AREA OF A SECTOR OF A CIRCLE THAT HAS A CENTRAL ANGLE
       OF 13∏/18 and a radius of 12cm. round your answer to the
       nearest tenth.
       >
       --- End Quote ---
       Remember that thw area with 13pi/18 is portion of the whole
       circle. So find the ratio between the 13pi/18 and 2pi, then that
       will be thw same ratio between the whole circle and the portion
       #Post#: 100--------------------------------------------------
       Re: Unit 4 forum
   DIR By: Keanu
       Date: November 16, 2014, 12:42 pm
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       5.1 (pg 100) #1
       "determin the maximum value, the minimum value and the values of
       x where they occur foor each function on the interval
       [-2pi,2pi]"
       1a) y = sinx-5
       I got the graph drawn correctly, but for the maximum i got -4 at
       -pi and for the minimum i got -6 at pi.
       The answers were different in the answer book
       Same problem for part b
       #Post#: 101--------------------------------------------------
       Re: Unit 4 forum
   DIR By: dadougiedude
       Date: November 16, 2014, 2:43 pm
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       --- Quote from: Keanu link ---
       >
       > 5.1 (pg 100) #1
       >
       > "determin the maximum value, the minimum value and the values
       of x where they occur foor each function on the interval
       [-2pi,2pi]"
       >
       > 1a) y = sinx-5
       >
       > I got the graph drawn correctly, but for the maximum i got -4
       at -pi and for the minimum i got -6 at pi.
       >
       > The answers were different in the answer book
       >
       > Same problem for part b
       >
       --- End Quote ---
       what is the answer of the book?
       #Post#: 102--------------------------------------------------
       Re: Unit 4 forum
   DIR By: dluvbell
       Date: November 18, 2014, 6:17 am
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       Remember when sine graph reaches max? It is not pi.
       Also for minimum, it's not pi either..
       Here is my lead. What is sin(pi/2)??
       You figure this out then u will figure the question you asked.
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