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#Post#: 4--------------------------------------------------
Unit 2 forum
DIR By: dluvbell
Date: September 25, 2014, 12:37 pm
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Unit 2
#Post#: 13--------------------------------------------------
HW Nelson version
DIR By: dluvbell
Date: October 2, 2014, 9:01 am
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Dividing Polynomial:P168 #1,2,5a) c) e), 6 a) c) e), 7,9c) d),
10,11,12,13,14
Factoring polynomial: P176 #1,2,3, 4-7 (a,c,e), 9-14
Sum and difference of cubes: pg 182 #4-8
Solving Polynomial equations: Pg1,2,6,7, (1,2,6,7 Just do a c
e),10,11,13,15,16
Solving linear inequality: Pg 213 # 1-7 (a, c, e), 13, 15
Solving polynomial inequaility: Pg 225 #1,2,5, 6 ace, 7ace, 8,
10,12-14
#Post#: 14--------------------------------------------------
Questions
DIR By: dluvbell
Date: October 2, 2014, 9:05 am
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Enjoy
#Post#: 56--------------------------------------------------
Re: Unit 2 forum
DIR By: dadougiedude
Date: October 9, 2014, 7:12 pm
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State the degree of the quotient for each of the following
division statements, if possible.
For example: pg168 2(a)
(x^4-15x^3+2x^2+12x-10) / (x^2-4)
Is there a way to solve the degree of the quotient without doing
the long division?
#Post#: 57--------------------------------------------------
Re: Unit 2 forum
DIR By: dluvbell
Date: October 10, 2014, 6:00 am
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--- Quote from: DaDougieDude link ---
>
> State the degree of the quotient for each of the following
division statements, if possible.
>
> For example: pg168 2(a)
> (x^4-15x^3+2x^2+12x-10) / (x^2-4)
>
> Is there a way to solve the degree of the quotient without
doing the long division?
>
--- End Quote ---
Yes. Think about what you need to multiply to x^2 so that it
will become the same as x^4.
#Post#: 58--------------------------------------------------
Re: Unit 2 forum
DIR By: dadougiedude
Date: October 10, 2014, 8:48 am
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--- Quote from: whatever link ---
>
> [quote author=DaDougieDude link=topic=4.msg56#msg56
date=1412899931]
> State the degree of the quotient for each of the following
division statements, if possible.
>
> For example: pg168 2(a)
> (x^4-15x^3+2x^2+12x-10) / (x^2-4)
>
> Is there a way to solve the degree of the quotient without
doing the long division?
>
--- End Quote ---
Yes. Think about what you need to multiply to x^2 so that it
will become the same as x^4.
[/quote]
Right.
So to find the remainder, long division is required, no?
#Post#: 59--------------------------------------------------
Re: Unit 2 forum
DIR By: levmark
Date: October 10, 2014, 9:08 am
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Yup
#Post#: 60--------------------------------------------------
Re: Unit 2 forum
DIR By: dluvbell
Date: October 10, 2014, 12:25 pm
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--- Quote from: DaDougieDude link ---
>
> [quote author=whatever link=topic=4.msg57#msg57
date=1412938824]
> [quote author=DaDougieDude link=topic=4.msg56#msg56
date=1412899931]
> State the degree of the quotient for each of the following
division statements, if possible.
>
> For example: pg168 2(a)
> (x^4-15x^3+2x^2+12x-10) / (x^2-4)
>
> Is there a way to solve the degree of the quotient without
doing the long division?
>
--- End Quote ---
Yes. Think about what you need to multiply to x^2 so that it
will become the same as x^4.
[/quote]
Right.
So to find the remainder, long division is required, no?
[/quote]
I assume what you mean by "solve the degree" is finding the
degree of the quotient. So then, you don't need long division.
Just consider the very first term of the quotient.
If you are looking for the remainder, then yes Long division is
required.
#Post#: 64--------------------------------------------------
Re: Unit 2 forum
DIR By: idk
Date: October 18, 2014, 9:14 pm
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McGraw-Hill Ryerson Workbook
pg. 32 #5
The volume, in cubic cm, of a rectangular box can be modeled by
the polynomial expression 2y³+y²-27y-36.
Determine possible dimensions of the box if the height, in cm,
is given by y+3
#Post#: 65--------------------------------------------------
Re: Unit 2 forum
DIR By: dadougiedude
Date: October 19, 2014, 11:37 am
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--- Quote from: idk link ---
>
> McGraw-Hill Ryerson Workbook
> pg. 32 #5
>
> The volume, in cubic cm, of a rectangular box can be modeled
by the polynomial expression 2y³+y²-27y-36.
> Determine possible dimensions of the box if the height, in cm,
is given by y+3
>
--- End Quote ---
you'll get two other factors (length*wide), if you factor
(2y³+y²-27y-36) by (y+3)
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