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#Post#: 139--------------------------------------------------
Re: exam
DIR By: dluvbell
Date: January 19, 2015, 6:14 am
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--- Quote from: DaDougieDude link ---
>
> do we get to review in the first hour?
>
--- End Quote ---
No. You get 30min. The exam starts at 7
#Post#: 140--------------------------------------------------
Re: exam
DIR By: dluvbell
Date: January 19, 2015, 7:12 am
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--- Quote from: Thomas link ---
>
> find the exact avlue of the following:
> a) log8(6)-log8(3)+log8(4)
> b) log64(6sqrt8)
> c) log9(3^7*5sqrt81)
>
--- End Quote ---
A) use the product and quotient law of log.
b) cant do without a calculator based on what you wrote.
c) change the base first then bring down the exponent to the
front.
#Post#: 141--------------------------------------------------
Re: exam
DIR By: dluvbell
Date: January 19, 2015, 7:13 am
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--- Quote from: DaDougieDude link ---
>
> given that sin x = 3/8 and x is obtuse, what is the value of
tan 2x?
>
> a) [-3sqrt55]/23
> b) [3sqrt55]/46
> c) [-3sqrt55]/55
> d) [3sqrt55]/55
>
--- End Quote ---
Drwa a triangle in second quad. Find the measurements of the
triangle. Find tanx. Then use double angle formula for tan.
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