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08:37:47 <justaname> Hi all. Does anyone have any hints on how to implement U< without using U<? I've been reading the source for CMForth and I see that U< is defined as `- 2/ 0<` but I can't for the life of me figure out how this is supposed to work.
08:39:20 <justaname> If U< one of those things that just need to be implemented in assembly then how do Mr. Moore's chips handle this? Is the argument that U< isn't really needed?
08:50:39 <pointfree> justaname: minus sets the two numbers to be relative to zero. 2/ centers the two numbers over zero. 0< checks the sign.
08:54:45 <pointfree> with the stack machines (or machine forth) forth is the assembly syntax.
08:56:35 <justaname> pointfree: Thanks for the hint. I'm not sure I quite understand "2/ centers the two numbers over zero". How would that be translated to e.g. gforth, so i could experiment with it? I tried `: U< - 2/ 0< ;` there but it didn't work as expected (or I screwed up somewhere)
08:58:27 <justaname> : MYU< - 2/ 0< ;  ok
08:58:27 <justaname> 5 -1 MYU< . 0  ok
08:58:27 <justaname> 5 -1 U< . -1  ok
08:58:27 <justaname> https://pastebin.com/t44cxd6j
08:59:05 <justaname> Sorry for that. I don't often use IRC. pastebin URL has the same thing in it.
09:00:27 <pointfree> justaname: It works for me: -2 1 - 2/ 0< . -1  ok 
09:00:33 <pointfree> 1 -2 - 2/ 0< . 0  ok
09:01:00 <pointfree> justaname: Maybe you redefined a word by mistake?
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09:03:17 <justaname> You're right! I don't know what I did there, but it's working now.
09:04:00 <pointfree> You restarted gforth?
09:04:23 <justaname> Thanks a lot pointfree... that was confusing. In the future I'll try restarting gforth when the world stops making sense.
09:04:53 <pointfree> np
09:05:10 <justaname> Yeah. I tried your code, which behaved as expected, so I restarted gforth and now it  works. I must have broken something.
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09:37:29 <justaname> pointfree: maybe I'm confusing myself here but it seems that `- 2/ 0<` implements U>, as the arguments seem to be reversed. Is that expected?
09:40:25 <johnmark_> what is mod vs. remainder in sm/rem (symmetric mixed divide and remainder) and fm/mod (floored mixed divide and modulo)?
09:40:46 <justaname> The definition in CMFORTH is `: U< ( u u - t)   - 2/  0< ; ( 3)` so it's clearly supposed to be U< but maybe Mr. Moore just decided the order wasn't important to the idea of an "unsigned comparison"
09:48:21 <justaname> https://github.com/ForthHub/cmFORTH/blob/master/cmforth.fth
09:49:22 <justaname> For reference. It seems the code is inconsistent. U< is used like it should be U< but the definition of U< appears to be U>
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13:27:03 <johnmark_> Floored: 3mod3=0 2mod3=2 1mod3=1 0mod3=0 -1mod3=2 -2mod3=1 -3mod3=0
13:27:03 <johnmark_> symmetric: 6%3=0, 5%3=2, 4%3=1, 3%3=0, 2%3=2, 1%3=1, 0%3=0, -1%3=-1, -2%3=-2, -3%3=0, -4=-1, -5%3=-2, -6%3=0
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15:23:07 <reepca> hm, trying to use gforth's libc.fs and errno isn't changing when it should.
15:36:42 <johnmark_> Someone was asking about a book on Forth.  There is a newer revision of this book buy you can get an idea of what he writes about.  https://www.disavowed.jp/ti/docs/fbForth_2.0_Manual_20150620.pdf
15:37:26 <johnmark_> The newer revision can be fond here: https://www.amazon.com/fbForth-2-0-File-Based-Cartridge-Implementation/dp/1973932679
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